We will find the shape of molecule by VSEPR theory...
To calculate hybridisation we need a formula... =no of valence electron present in central atom +no of monovalent atom +-charge/2
For example... XeO2F2
In Xe atom eight valence electron present in outermost shell.
Here, no of monovalent atom are =2
Here, oxygen is a divalnet atom. So we cannot add the no of oxygen.
In XeO2F2 molecule has no charge.
:put the value in the Formula= 8+2/2=5
5 means there is 5 orbitals participate in the shape of molecule.
One s, three p and one d orbital ，it means there is sp3d hybridisation.
The geometry of the molevule is trigonal bi pyramidal.
But we know that there is 5 orbital participate in hybridisation but there is only 4 side atom which means there is a lone pair present.
:the shape of molecule is "
sea saw"
We also know that the lone pair occupy always equitorial position and more electronegative atom occupy axial position.
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