Question related to calculation of E.N.

 


Ques:Two elwment A&B are such that the bond energy of A-A molecule &B-B molecule & A-B molecule are 81,  64 and 76 respectively. If E.N. of atom A is 2.4 than find out the E.N. of atom A in mulliken  Scale.

Ans:-  delta  = 76-√81*64

= 76-9*8 = 4


Xa-Xb = 0.208√4

            = 0.208*2

            = 0.416

Xa-2.4 = 0.416

      Xa= 0.416+2.4

           = 2.816


2.816 = E.A+I.P/2*2.8

    7.3 = E.A +I. P/2

X(mulliken)= 7.3

Previous
Next Post »

If you have any doubts, Please let me know ConversionConversion EmoticonEmoticon